Question 1: A piece of rusted iron was analysed to find out how much of the iron had been oxidised to rust [hydrated iron(III) oxide]. A small sample of the iron was dissolved in excess dilute sulfuric acid to give 250 cm3 of solution. The solution contains Fe2+ ions from the unrusted iron dissolving in the acid, and, Fe3+ ions from the rusted iron.
(a) 25.0 cm3 of this solution required 16.9 cm3 of 0.0200 mol dm–3 KMnO4 for complete oxidation of the Fe2+ ions.
Calculate the moles of Fe2+ ions in the sample titrated.
(b) To a second 25.00 cm3 of the rusted iron solution an oxidising agent was added to convert all the Fe2+ ions present to Fe3+ ions. The Fe3+ ions were titrated with a solution of EDTA4–(aq) ions and 17.6 cm3 of 0.100 mol dm–3 EDTA were required.
Assuming 1 mole of EDTA reacts with 1 mole of Fe3+ ions, calculate the moles of Fe3+ ions in the sample.
(c) From your calculations in (a) and (b) calculate the ratio of rusted iron to unrusted iron and hence the percentage of iron that had rusted.
QUESTION 2 Given the following two half–reactions
(a) Given (i) S4O62–(aq) + 2e– ==> 2S2O32–(aq)
and (ii) I2(aq) + 2e– ==> 2I–(aq)
construct the full ionic redox equation for the reaction of the thiosulfate ion S2O32– and iodine I2.
(b) what mass of iodine reacts with 23.5 cm3 of 0.0120 mol dm–3 sodium thiosulfate solution.
(c) 25.0 cm3 of a solution of iodine in potassium iodide solution required 26.5 cm3 of 0.0950 mol dm–3 sodium thiosulfate solution to titrate the iodine.
What is the molarity of the iodine solution and the mass of iodine per dm3?
Question 3: 2.83 g of a sample of haematite iron ore [iron (III) oxide, Fe2O3] were dissolved in concentrated hydrochloric acid and the solution diluted to 250 cm3.
25.0 cm3 of this solution was reduced with tin(II) chloride (which is oxidised to Sn4+ in the process) to form a solution of iron(II) ions.
This solution of iron(II) ions required 26.4 cm3 of a 0.0200 mol dm–3 potassium dichromate(VI) solution for complete oxidation back to iron(III) ions.
(a) given the half–cell reactions
(i) Sn4+(aq) + 2e– ==> Sn2+(aq)
and (ii) Cr2O72–(aq) + 14H+(aq) + 6e– ==> 2Cr3+(aq) + 7H2O(l)
deduce the fully balanced redox equations for the reactions
(i) the reduction of iron(III) ions by tin(II) ions
(ii) the oxidation of iron(II) ions by the dichromate(VI) ion
(b) Calculate the percentage of iron(III) oxide in the ore.
(c) Suggest why potassium manganate(VII) isn’t used for this titration? (though it was ok in Q1)
If you don’t know, the following half-cell potential data will help!
Eθ = +1.33 for Cr2O72–(aq) + 14H+(aq) + 6e–
2Cr3+(aq) + 7H2O(l) Eθ = +1.36 for Cl2(aq) + 2e–
2Cl–(aq) Eθ = +1.51 for MnO4–(aq) + 8H+(aq) + 5e–
Mn2+(aq) + 4H2O(l)
Question 4: An approximately 0.02 mol dm–3 potassium manganate(VII) solution was standardized against precisely 0.100mol dm–3 iron(II) ammonium sulfate solution. 25.0 cm3 of the solution of the iron(II) salt were oxidized by 24.15 cm3 of the manganate(VII) solution.
What is the molarity of the potassium manganate(VII) solution ?
Question 5: 10.0 g of iron(II) ammonium sulfate crystals were made up to 250 cm3 of acidified aqueous solution. 25.0 cm3of this solution required 21.25 cm3 of 0.0200 mol dm–3 potassium dichromate(VI) for oxidation.
Calculate x in the formula FeSO4.(NH4)2SO4.xH2O
Question 6: Given the half–reaction C2O42–(aq) – 2e– ==> 2CO2(g)
or H2C2O4(aq) – 2e– ==> 2CO2(g) + 2H+(aq)
(a) write out the balanced redox equation for manganate(VII) ions oxidising the ethanedioate ion (or ethanedioic acid).
(b) 1.520 g of ethanedioic acid crystals, H2C2O4.2H2O, was made up to 250.0 cm3 of aqueous solution and 25.00 cm3 of this solution needed 24.55 cm3 of a potassium manganate(VII) solution for oxidation.
Calculate the molarity of the manganate(VII) solution and its concentration in g dm–3.
Question 7: A standardization of potassium manganate(VII) solution yielded the following data:
0.150 g of potassium tetraoxalate dihydrate, KHC2O4.H2C2O4.2H2O needed 23.20 cm3 of the manganate(VII) solution.
What is the molarity of the manganate(VII) solution? Use the equation and reasoning from Q6 to help you.
Question 8: Given the half–cell equation O2(g) +2H+(aq) + 2e– ==> H2O2(aq)
(a) construct the fully balanced redox ionic equation for the oxidation of hydrogen peroxide by potassium manganate(VII)
(b) 50.0 cm3 of solution of hydrogen peroxide were diluted to 1.00 dm3 with water.
25.0 cm3 of this solution, when acidified with dilute sulfuric acid, reacted with 20.25 cm3 of 0.0200 mol dm–3KMnO4.
What is the concentration of the original hydrogen peroxide solution in mol dm–3?
Question 9: 13.2 g of iron(III) alum were dissolved in water and reduced to an iron(II) ion solution by zinc and dilute sulfuric acid. The mixture was filtered and the filtrate and washings made up to 500 cm3 in a standard volumetric flask.
If 20.0 cm3 of this solution required 26.5 cm3 of 0.0100 mol dm–3 KMnO4 for oxidation.
(a) give the ionic equation for the reduction of iron(III) ions by zinc metal.
(b) Calculate the percentage by mass of iron in iron alum.
Question 10: Calculate the concentration in mol dm–3 and g dm–3, of a sodium ethanedioate (Na2C2O4) solution, 5.00 cm3of which were oxidized in acid solution by 24.50 cm3 of a potassium manganate(VII) solution containing 0.05 mol dm–3.
Question 11: Calculate x in the formula FeSO4.xH2O from the following data:
12.18 g of iron(II) sulfate crystals were made up to 500 cm3 acidified with sulfuric acid.
25.0 cm3 of this solution required 43.85 cm3 of 0.0100 mol dm–3 KMnO4 for complete oxidation.
Question 12: Given the half–reaction NO3–(aq) + 2H+(aq) + 2e– ==> NO2–(aq) + H2O(l)
(a) give the ionic equation for potassium manganate(VII) oxidising nitrate(III) to nitrate(V)
(b) 24.2 cm3 of sodium nitrate(III) [sodium nitrite] solution, added from a burette, were needed to discharge the colour of25.0 cm3 of an acidified 0.0250 mol dm–3 KMnO4 solution.
What was the concentration of the nitrate(III) solution in grammes of anhydrous salt per dm3?
Question 13: 2.68 g of iron(II) ethanedioate, FeC2O4, were made up to 500 cm3 of acidified aqueous solution. 25.0 cm3 of this solution reacted completely with 28.0 cm3 of 0.0200 mol dm–3 potassium manganate(VII) solution.
Calculate the mole ratio of KMnO4 to FeC2O4 taking part in this reaction. Give the full redox ionic equation for the reaction.
Question 14: Given the half–cell reaction IO3–(aq) + 6H+(aq) + 5e– ==> 1/2I2(aq) + 3H2O(l) (see also Q2)
(a) Deduce the redox equation for iodate(V) ions oxidising iodide ions.
(b) What volume of 0.0120 mol dm–3 iodate(V) solution reacts with 20.0 cm3 of 0.100 mol dm–3 iodide solution?
(c) 25.0 cm3 of the potassium iodate(V) solution were added to about 15 cm3 of a 15% solution of potassium iodide (ensures excess iodide ion). On acidification, the liberated iodine needed 24.1 cm3 of 0.0500 mol dm–3 sodium thiosulfate solution to titrate it.
(i) Calculate the concentration of potassium iodate(V) in g dm–3
(ii) What indicator is used for this titration and what is the colour change at the end–point?
Question 15: 25.0 cm3 of an iodine solution was titrated with 0.100 mol dm–3 sodium thiosulfate solution and the iodine reacted with 17.6 cm3 of the thiosulfate solution.
(a) give the reaction equation.
(b) what indicator is used? and describe the end–point in the titration.
(c) calculate the concentration of the iodine solution in mol dm–3 and g dm–3.
Question 16: This question involves titrating ethanedioic acid (oxalic acid), H2C2O4 or (COOH)2 (i) with standard sodium hydroxide solution and then with potassium manganate(VII) solution (potassium permanganate, KMnO4).
The titration data is as follows:
10 cm3 of a H2C2O4 solution required 8.50 cm3 of a 0.20 mol dm-3 (0.20M) solution of sodium hydroxide for complete neutralisation using phenolphthalein indicator (first permanent pink end-point).
10 cm3 of the same H2C2O4 solution required 8.20 cm3 of a KMnO4 solution for complete oxidation to carbon dioxide and water in the presence of dilute sulfuric acid to further acidify the ethanedioic acid solution (first permanent pink end-point).
(a) Write an equation for the neutralisation reaction of ethanedioic acid with sodium hydroxide.
(b) Calculate the moles of H2C2O4 in the solution and the molarity of the ethanedioic acid solution.
(c) Given the following half-reactions:
(i) MnO4–(aq) + 8H+(aq) + 5e– ===> Mn2+(aq) + 4H2O(l)
(ii) H2C2O4(aq) – 2e– ===> 2CO2(g) + 2H+(aq)
Deduce the full redox titration equation for the oxidation of ethanedioic acid by potassium manganate(VII).
(d) From the equation in (c) and the titration data, deduce the molarity of the potassium manganate(VII) solution.
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