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MEASURES (LENGTH)
A measure is a mathematical object that quantifies the size of sets. Each distinct measure embodies a different way to assess how big a set is. At first thought, it would seem that there is only one natural measure of a set’s size—its cardinality.
Units of length from the biggest to the smallest.
Km Hm Dm m dm cm mm
1 0 0 0 0 0 0
1 0 0 0 0 0
1 0 0 0 0
1 0 0 0
1 0 0
1 0
Expressing metres as centimetres
m dm cm
1 0 0
1m = 100cm
Big to small you multiply (x)
6m = (6 x 100)
= 600cm
m dm cm
1 0 0
1m = 100cm
Big to small = (x)
2 ½ m = 2 + ½
= (2 x 100)cm +(1/2 x 100)cm
= 200cm + 50cm
= 250cm.
Or;
Change 2 ½ m into an improper fraction
2 1/2m = 5/2m
= 5/2 x 100
= 5 x 50
= 250cm
WEEK SEVEN.
LESSON TWO.
Expressing centimetres to metres
m dm cm
1 0 0
100cm = 1m
mall to big you divide (÷)
400cm = 400
100
= 4 ÷ 1
= 4m
m dm cm
1 0 0
100cm = 1m
Small to big you divide (÷)
1900cm = 1900
100
= 19 ÷ 1
= 19m
WEEK SEVEN.
LESSON THREE.
Converting centimetres to metres and cm
m dm cm
1 0 0
100cm = 1m
120cm = 100cm + 20cm
Small to big you divide (÷)
120cm = 100 + 20cm
100
= 1 ÷ 1 + 20cm
= 1m 20cm
m dm cm
1 0 0
100cm = 1m
840cm = 800cm + 40cm
Small to big = (÷)
840cm = 800 + 20cm
100
= 8 ÷ 1 + 40cm
= 8m 40cm
LESSON FOUR.
Addition of metres and centimeters
1
m cm SW 45
2 45 + 36
+ 6 36 81
8 81
1
m cm SW 25 110
8 25 + 85 100
+ 6 85 110 1 r 10
15 10
LESSON FIVE.
Subtraction of metres and centimetres
6 80 80
– 2 60 – 60
4 20 20
9 24 1m = 100ccm 0 x 124
–5 30 100 + 24 = 124 – 30
3 94 094
m cm SW
3 70 70
– 1 20 – 20
2 50 50
LESSON ONE.
Multiplication of metres and centimetres
m cm SW 25 150
61 25 x 6 100
x 6 150 1 r 50
37 50
m cm SW 45 135
31 45 x 3 100
x 3 135 1 r 35
10 53
LESSON TWO.
Expressing Km to metres
Km Hm Dm m
1 0 0 0
1Km = 1000m
7Km = (7 x 1000)m
= 7000m
Km Hm Dm m
1 0 0 0
1Km = 1000m
4 ½ Km = 4 + ½ Km
= (4 x 1000)m + (1/2 x 1000)m
= 4000m + 500m
= 4500m
LESSON THREE.
Expressing metres to Km.
1000m = 1Km
3000m = 3000 Km
1000
= 3 ÷ 1
= 3Km
1000m = 1Km
2000m = 2000 Km
1000
= 2 ÷ 1
= 2Km
LESSON FOUR.
Perimeter of a Rectangle and Square
Find the perimeter of the following.
Perimeter = Length + Width + Length + Width
= L + W = L = W
= (12cm + 4cm) + (12cm + 4cm)
= 16cm + 16cm
= 32cm
Perimeter = Side + Side +Side +Side = S + S + S + S
= 6cm + 6cm +6cm + 6cm
= 36cm
WEEK EIGHT.
LESSON Five.
Area of a rectangle and a square
Area = L X W
= 12 cm x 4 cm
= 48 cm2.
= 6 cm x 6 cm
= 36 cm2
WEEK NINE.
LESSON ONE.
Area and Perimeter of a triangle
Area of a rectangle = L X W
= 6cm x 4cm
= 24cm2
_________________________________________________________________________Area of the shaded part is half the area of the rectangle.
= 24cm2 ÷ 2
= 12cm2
Area of a triangle = ½ x base x height
= ½ x b x h
= ½ x 6cm x 4cm
= 12cm2
Find the area of the triangle.
Height = 3cm
Base = 4cm height = 3cm
Area = ½ x b x h Base = 4cm
= ½ x 4cm x 3cm
= 2cm x 3cm
= 6cm2
_________________________________________________________________________Calculate the Perimeter
Perimeter = S + S + S
= 10cm + 4cm + 3cm
= 17cm
Find the area and perimeter of the triangle shown.
Height = 4cm
Area = ½ x b x h
= ½ x 10cm x 4cm
= 10cm x 2cm
= 20cm2
________________________________________________________________________Perimeter = S + S + S
= 9cm + 6cm + 10cm
= 15cm + 10cm
= 25cm
WEEK NINE.
LESSON TWO.
Finding the missing side of a rectangle
Sketch:
6cm x W = 24cm2
6Wcm= 24cm2
W = 24 cm2
6cm
W = 4cm
_________________________________________________________________________Find the length of a rectangle whose width is 5cm if its area is 60cm2.
Sketch:
L x 5cm = 60cm2
5Lcm= 60cm2
L = 60 cm2
5cm
L = 12cm
___________________________________________________
WEEK NINE.
LESSON THREE.
Finding the side of a square given its perimeter
Find its sides.
Sketch:
S + S + S + S = P
4S = 20cm
4 4
S = 5cm
Find its area. Area = Side x Side
= S x S
= 5cm x 5cm
= 25cm2
S + S + S + S = 24m
P = 24m x
x + x + x + x = 24m
4x = 24m
4x = 24m
4 4
X = 6m
WEEK NINE.
LESSON FOUR.
Addition of area
Find the area of the figure.
Area = Area of A + Area of B
= (L x W) + (L x W)
= (7cm x 4cm) + (6cm x 3cm)
= 28cm2 + 18cm2
= 46cm2
Subtraction of area
Given the figure below, use it to answer the questions that follow.
A = L x W
= 6m x 2m
= 12m2
A = L x W
= 10m x 4m
= 40m2
Area of the shaded part = Area of big rectangle – Area of small rectangle
= 40m2 – 12m2
4 0
– 1 2
2 8m2
Attachments
Assignment
Attachments12
ASSIGNMENT : Measures assignment MARKS : 10 DURATION : 1 week, 3 days